(x^2-1)(x^2+2x-19)=0

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Solution for (x^2-1)(x^2+2x-19)=0 equation: 


Simplifying
(x2 + -1)(x2 + 2x + -19) = 0

Reorder the terms:
(-1 + x2)(x2 + 2x + -19) = 0

Reorder the terms:
(-1 + x2)(-19 + 2x + x2) = 0

Multiply (-1 + x2) * (-19 + 2x + x2)
(-1(-19 + 2x + x2) + x2(-19 + 2x + x2)) = 0
((-19 * -1 + 2x * -1 + x2 * -1) + x2(-19 + 2x + x2)) = 0
((19 + -2x + -1x2) + x2(-19 + 2x + x2)) = 0
(19 + -2x + -1x2 + (-19 * x2 + 2x * x2 + x2 * x2)) = 0
(19 + -2x + -1x2 + (-19x2 + 2x3 + x4)) = 0

Combine like terms: -1x2 + -19x2 = -20x2
(19 + -2x + -20x2 + 2x3 + x4) = 0

Solving
19 + -2x + -20x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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